Math, asked by NamraAnsari699, 6 months ago

Find the principal on which a simple interest of 55 will be obtained after 9 months at the rate of 11/3 per annum.

Answers

Answered by Anonymous
7

Correct Answer:

C) 2000

Description for Correct answer:

Let, principal = P

Given, SI = 55, Time t = 9 months =912yr

Rate r = 323%= 113%

SI = P×r×t100

=> P = 100×SIR×T

=> 55×10011×9×3×12=2000

Principal (P) = RS. 2000

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Answered by kirtansoni09
1

P=₹166.67

Step-by-step explanation:

Here, Simple interest = ₹55

Time = 9 months

Rate = 11/3

Now,simple interest = P×T×R/100

55 = p \times 9 \times  \frac{11}{3} \times  \frac{1}{100}

55 \times  \frac{1}{9}  \times  \frac{3}{11} \times 100 = p

P = 500/3

P = ₹166.666

So,P = ₹166.67

Hence,the principal amount is ₹166.67

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