Question

find the principal that will amount to Rupees 2240 at 4% per annum simple interest in 3 years

Answer 1

The principal is Rs.2000

Step-by-step explanation:

Let the principal be x

Time = 3 years

Rate of interest = 4%

Amount = Rs.2240

Simple interest = Amount - Principal = 2240-x

Formula :$SI = \frac{P \times T \times R}{100}$

$2240-x=\frac{x \times 3 \times 4}{100}$

$100(2240-x)=12x$

$224000-100x=12x$

$224000=112x$

$\frac{224000}{112}=x$

2000 = x

Hence The principal is Rs.2000

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Find the amount if principal is 3210 and interest is 5%

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Answer 2

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\therefore{\text{Principal=2000\:rupees}}}$

$\green{\therefore{\text{S.I=240\:rupees}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{ \underline \bold{Given : }} \\ : \implies \text{Time (t)= 3\:years} \\ \\ : \implies \text{Amount(A) = 2240\:rupees} \\ \\ : \implies \text{Rate(r) = 4\%} \\ \\ \red{ \underline \bold{To \: Find: }} \\ : \implies \text{Simple\:interest(S.I) = ?}\\\\ :\implies \text{Amount=?}$

• According to given question :

$:\implies Amount=S.I+Principal\\\\ :\implies 2240=SI+p\\\\ :\implies S.I=2240-p\\\\ \bold{As \: we \: know \: that } \\ \circ \: \text{Simple \: interest} = \frac{ \text{Principal }\times \text{ Rate} \times \text{Time}}{100} \\ \\ \bold{Putting \: given \: values} \\ : \implies S.I = \frac{p \times r \times t}{100} \\ \\ : \implies 2240-p = \frac{p \times 4\times3}{100} \\ \\ : \implies 2240-p= \frac{12p }{100 } \\ \\ :\implies 224000-100p=12p\\\\ :\implies 112p=224000\\\\ :\implies p=\frac{224000}{112} \\\\ \green{ : \implies \text{p= 2000\: rupees}} \\ \\ \green{ \therefore \text{Principal=2000\: rupees}} \\ \\ :\implies Amount=S.I+principal\\\\ \green{:\implies\text{S.I=2240-2000=240\:rupees}} \\ \\ \bold{Basic \: formula\:related\:to\:C.I} \\ \circ \: A = p(1 + \frac{r}{100} )^{t}$