Math, asked by muskanparvin508, 8 months ago

find the principal that will yield an interest of rupees 367.50 in 9/2 years at 10/3per cent per annum​

Answers

Answered by bivan
8

Answer:

₹2448

Step-by-step explanation:

36750/100 = (p×9/2×10/3)/100

=> 36750 = p×9/2×10/3

(because 100 is in both sides, thus it will be cancelled)

=> 36750 = 90p/6

=> 36750 = 15p

=> 15p = 36750

=> p = 36750/15

=> p = 2448

Therefore the principal is ₹2448.

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Answered by savitasavi67
0

Answer:

₹2050

Step-by-step explanation:

given: interest=367.50

time=9/2 years

rate=10/3

S.I= PRT/100

36750/100= (p×10/3×9/2)/100

36750 = 15p

p= 36750/15=2450(ans)

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