Find the principal value of loge(-3)
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Let’s start with log(−1) , since that one we know: log(−1)=πi(+2kπ) for any k∈Z.
Also, we know that log(ab)=log(a)+log(b)
So, we get that log(−3)=log(3)+πi+(2kπ),k∈Z. Here log(3) will just be the ordinary (real) logarithm of 3. The principal value is log(3)+πi.
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