Math, asked by rr1304699, 9 months ago

find the principal value of sin^-1 (√3-1/2√2)​

Answers

Answered by Anonymous
2

Step-by-step explanation:

 \sin(15 )  = ( \sqrt{3 }  - 1) \div 2 \sqrt{2}

so the principle value is 15 degree

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