Math, asked by ulfatfatma555, 1 month ago

find the principal when s.i =1000. p=1 years r=10% solution​

Answers

Answered by HARSHMAHAMUNI
0

Answer:

p = 10000

Step-by-step explanation:

SI= \frac{PRT}{100}

SI = 1000

P = p

r = 10%

t* = 1

1000 = 1 * 10 * p / 100

1000 = p / 10

10000 = p

∴ Principal = 10000

Answered by divideandci
1

Answer:

your answer is 10,000

Step-by-step explanation:

s.i=p*r*t/100

1000=p*10*1/100

1000=p*1/10

1000=p/100

10*1000=p

1000=p

i hope this helps :)

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