Question

Find the probability distribution of number of heads when one coin is throwing two times

Answer 1

Probability Distributoon= {H,T} , {H,T} , {H,T}

Answer 2

Answer:

Step-by-step explanation:

Given: one coin is tossed twice, we can write the sample space as follows: S = {HH, HT, TH, TT}.

Since all these 4 events are equally likely, P(HH) = P(HT) = P(TH) = P(TT) = 14

Let X be the number of heads in S such that → X(HH) = 2, X(HT) = 1, X(TH) = 1 and X(TT) = 0. It follows that:

P(X = 0) = P (TT) = 14

P(X = 1) = P(TH, HT) = 24=12

P(X = 2) = P(HH) = 14