Find the probability that a non leap year contains 53 mondays
Answers
Answered by
2
Hey buddy
As it's a non leap year
the answer is
1/7
Hope it's helpful for you dear
Answered by
1
Answer:
1/7
Step-by-step explanation:
We know that there are 52 weeks in a year.
There are 7 days in a week
52 weeks will be to 7*52=364 days.
The remaining 1 day can be any day among Monday, Tuesday,..., Sunday.
Sample space has seven days as options.
So probability of getting 53 Sundays in a non-leap year is 1/7
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