Question

find the probability in a leap year of getting
1) 53 Sundays
2)only 52 Sundays
3) 54 Sundays

please answer fast.
​

Answer 1

Answer:

a leap year consist 366 days and that mean 52 weaks and 2 days

total outcome = 7 { sun,mon ; mon ,tues; tues ,wed ; wed ,thu ; thu ,Fri ; Fri ,sat ; sat ,sun; }

favourable outcomes = 2 ( since those two days can be {sun,mon ; sat , sun;}

P( E) = favourable outcomes/ total outcomes

(1.) P(E) = 2/7

(2.) P(E') = 1- P(E)

P(E') = 5/7

(3.) P ( 54 Sundays) = 0

{ since it could not be possible}

hope it will help you

plz mark me as brainiest.

Answer 2

Answer:

(1) P(E) = 1/7

(2) P(E') = 1-1/7 = 6/7

(3) P(E) = 0