If sec theta =m+n/2rootmn,find sin theta.
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Step-by-step explanation:
we know pythagorus therom ac^2=ab^2+bc^2
so,(m+n)^2=4mn-ab^2
ab^2=m^2+n^2-2mn
ab^2=(m-n)^2
ab=m-n
therefore,sin theta=Opp.side/Hyptenuse
sin theta=m-n/m+n
Hope you will understand
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