Question

Find the probability of :
(1) Getting a tail when a coin is tossed.
(it) Getting the number 4 when a dice is
thrown.
(iii) Getting an odd number when a dice
is thrown.
(iv) Getting 2 heads when a coin is
tossed
(v) Getting a number less than 1 when a
dice is thrown.
(vi) Getting a prime number when a dice
is thrown
mach
ch of the following​

Answer 1

Answer:

mam aap mere answer ka answer dedo 6th class

Answer 2

Step-by-step explanation:

1st part

p(e) = no.of favourable outcomes / no.of total outcomes

here, the outcomes can be

head

tail

here, we can find that only one outcome is favourable and there are total of 2 outcomes

therefore , p(e) = 1/2

2nd part

p(e) = no.of favourable outcomes / total no.of outcomes

here, the outcomes can be

1

2

3

4

5

6

here, we can find that only 1 outcomes is favourable and there are total of 6 outcomes

therefore, p(e) = 1/6

3rd part

p(e)= no.of favourable outcomes / no.of total outcomes

here , the outcomes can be

1

2

3

4

5

6

here, we can find that odd nos. are 1,3,5 . therefore 3 outcomes are favourable out of total of 6 outcomes

therefore, p(e)=3/6 = 1/2

4th part

p(e) = no.of favourable outcomes / no.of total outcomes

here, the outcomes can be

head

tail

here , we can find their it is impossible to have 2 heads when only one coin is tossed,

therefore , probability = 0

5th part

p(e) = no.of favourable outcomes / total no. of outcomes

here, the outcomes can be

1

2

3

4

5

6

here, there is no outcome less than 1

therefore , probability = 0

6th part

p(e) = no.of favourable outcomes / total no.of outcomes

here , the outcomes can be

1

2

3

4

5

6

here , the prime nos. are 2,3,5

therefore , the favourable outcomes are 3 and total outcomes are 6

therefore , p(e) = 3/6 = 1/2