find the probability of a leap year having i) 53 fridays ii) exactly 52 sundays
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Answer:
Step-by-step explanation:
Of these total 7 outcomes, the favourable outcomes are 1. Hence the probability of getting 53 sundays = 1 / 7. ∴ probability of getting 52 sundays = 1 - 1/ 7 = 6 / 7. A year has 52 weeks.
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Answer:
2/7
Step-by-step explanation:
1. only pair consists of 366 days i.e. 52 week and two days remaining
only pair consists of 366 days i.e. 52 week and two days remaining these two days can be:-
only pair consists of 366 days i.e. 52 week and two days remaining these two days can be:-(Monday Tuesday), (Tuesday Wednesday ),(Wednesday Thursday), (Thursday Friday), (Friday Saturday), (Saturday Sunday)
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