Question

Find the probability of getting 53 Friday in a leap year

Answer 1

A leap year consists of 366 days.i.e 52 weeks and 2 days remaining.

These 2 days can be any of the following:

(Mon, Tues),(Tues,Wed),(Wed,Thurs),(Thurs,Fri),(Fri,Sat),(Sat,sun).

The number of cases = 7.

The number of cases in which we get a Friday = 2.


The probability of getting 53 Fridays in a leap year = 2/7.


Hope this helps!

Answer 2

Answer:

There are 366 days in a leap year that is 2 more than 52 full weeks

52×7 + 2 = 366

Therefore now for the last 2 days, there could be 7 possibilities all equally likely. These are:

Monday, Tuesday

Tuesday, Wednesday

Wednesday, Thursday

Thursday, Friday  

Friday, Saturday

Saturday, Sunday

Sunday, Monday

There are 2 cases out of the 7 cases above such that there is an extra friday.

Therefore the required probability here is 2 / 7