find the probability of getting 53 Fridays in a leap year?
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2/7 is the correct answer
because there are 52 weeks in the year
1week =7 days
366÷7 =quotient 52
remainder 2
so there are 2 days remaining
so the
possibilities are
sun,mon
mon,tue,
tue,wed
wed,thr,
thr,fri
fri,sat
sat,sun
barath93:
please mark as brainlist answer
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