Question

find the probability of getting 53 Saturdays in 2002.
(explanation is must).

Answer 1

2002 isn't a leap year... Therefore the year has 365 days.
No of weeks in a year is 52
So, 52 weeks has 364 days...The single day extra can be any day in that week.

Therefore, probability will be 1/7
As there are 7 days in a week...And only one day can be a Saturday.

Hope this helps you..

Answer 2

Answer:

1/7

Step-by-step explanation:

2002 is a non-leap year.

Now,

We know that there are 365 days in a non-leap year.

365 = 7 * 52 + 1.

∴ A non-leap year will consist at least 52 Saturdays. The possibility for the remaining 1 day is:

(i) Saturday (iii) Sunday (iii) Monday (iv) Tuesday (v) Wednesday (vi) Thursday (vii) Friday.

Let A be the event of getting 53 Saturdays in a non-leap year. Therefore, only (i) possibility is favorable to the event A.

Therefore, Required probability = P(A) = 1/7

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