Find the probability of getting 53 Sundays in a non leap year
Answers
Answered by
4
Mate here is your answer
Attachments:
![](https://hi-static.z-dn.net/files/daa/0e2a51c7f2db8ad25be0f7d66227700f.jpg)
Answered by
1
Answer:
We know that A non-leap year consists of 365 days.
In 365 days, Number of weeks = 52 and 1 day remaining.
For 52 weeks, There will be 52 Sundays.The remaining 1 day can be either Sunday, Monday, Tuesday, Wednesday, Thursday, Friday, and Saturday.
Out of these 7 total outcomes, the favorable outcomes are 1.
Hence the probability of getting 53 Sundays = 1/7.
Hope this helps!
Similar questions