Math, asked by meenu2002, 10 months ago

Find the probability of getting 53 Sundays in a non leap year​

Answers

Answered by JasonJacob
4

Mate here is your answer

Attachments:
Answered by Pratik021205
1

Answer:

We know that A non-leap year consists of 365 days.

In 365 days, Number of weeks = 52 and 1 day remaining.

For 52 weeks, There will be 52 Sundays.The remaining 1 day can be either Sunday, Monday, Tuesday, Wednesday, Thursday, Friday, and Saturday.

Out of these 7 total outcomes, the favorable outcomes are 1.

Hence the probability of getting 53 Sundays = 1/7.

Hope this helps!

Similar questions