Math, asked by bavaganga000, 9 months ago

find the probability of getting 53 Tuesdays in ordinary year​

Answers

Answered by sanjuambastha
1

Answer:

So, to get 53 Tuesdays, we have to select one more Tuesday from these 7 possibilities with Probability 17. Hence, favourable outcomes =2 and total outcomes = 7. Therefore, probability of having 53 Tuesdays in a leap year is 1×27=27

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Answered by mahaksaini32
4

Answer:

1 year =365 days

A year has 52 weeks. Hence there will be 52 Tuesdays for sure.

52 weeks =52×7=364 days

365−364=2 days

In an ordinary year, there will be 52 Tuesdays and 1 day will be left.

This 1 day can be:

Sunday

Monday

Tuesday

Wednesday

Thursday

Friday

Saturday

Of these total 7 outcomes, the favourable outcomes are 1.

Hence the probability of getting 53 Tuesdays in an ordinary year is = 1/7

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