find the probability of getting 53 Tuesdays in ordinary year
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1
Answer:
So, to get 53 Tuesdays, we have to select one more Tuesday from these 7 possibilities with Probability 17. Hence, favourable outcomes =2 and total outcomes = 7. Therefore, probability of having 53 Tuesdays in a leap year is 1×27=27
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Answered by
4
Answer:
1 year =365 days
A year has 52 weeks. Hence there will be 52 Tuesdays for sure.
52 weeks =52×7=364 days
365−364=2 days
In an ordinary year, there will be 52 Tuesdays and 1 day will be left.
This 1 day can be:
Sunday
Monday
Tuesday
Wednesday
Thursday
Friday
Saturday
Of these total 7 outcomes, the favourable outcomes are 1.
Hence the probability of getting 53 Tuesdays in an ordinary year is = 1/7
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