find the probability of getting 53 wednesday in a leap year
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TE ANSWER IS 2/7
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1 year = 365 days
A leap year has 366 days
A year has 52 weeks. Hence there will be 52 Wednesdays.
52 weeks = 52 x 7 = 364 days
366 – 364 =2 days
In a leap year there will be 52 Wednesdays and 2 days will be left.
These 2 days can be:
(Sun,Mon)
(Mon,Tue)
(Tue, Wed)
(Wed,Thu)
(Thu,Fri)
(Fri,Sat)
(Sat,Sun)
Of these total 7 outcomes, the favorable outcomes are 2.
Hence the probability of getting 53 Wednesdays in a leap year = 2/7.
A leap year has 366 days
A year has 52 weeks. Hence there will be 52 Wednesdays.
52 weeks = 52 x 7 = 364 days
366 – 364 =2 days
In a leap year there will be 52 Wednesdays and 2 days will be left.
These 2 days can be:
(Sun,Mon)
(Mon,Tue)
(Tue, Wed)
(Wed,Thu)
(Thu,Fri)
(Fri,Sat)
(Sat,Sun)
Of these total 7 outcomes, the favorable outcomes are 2.
Hence the probability of getting 53 Wednesdays in a leap year = 2/7.
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