phythagorean triplet whose one of the members is 18
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Answered by
5
Pythagoras triplets are-
2m
m^2+1
m^2-1
let 2m be 18
m=9
9×9+1=82
9×9-1=80
Triplets
18,82,80
2m
m^2+1
m^2-1
let 2m be 18
m=9
9×9+1=82
9×9-1=80
Triplets
18,82,80
Answered by
3
hiii!!!
here's ur answer...
Pythagoras triplets are 2n, n²+1 and n²-1
let 18 be 2n
therefore n=18/2
=9
1. 18
2. n²+1
=9²+1
=81+1
=82
3. n²-1
=9²-1
=81-1
=80
hence the three Pythagoras triplets are 18,82 and 80.
hope this helps..!
here's ur answer...
Pythagoras triplets are 2n, n²+1 and n²-1
let 18 be 2n
therefore n=18/2
=9
1. 18
2. n²+1
=9²+1
=81+1
=82
3. n²-1
=9²-1
=81-1
=80
hence the three Pythagoras triplets are 18,82 and 80.
hope this helps..!
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