Question

phythagorean triplet whose one of the members is 18

Answer 1

Pythagoras triplets are-

2m
m^2+1
m^2-1

let 2m be 18

m=9

9×9+1=82
9×9-1=80

Triplets

18,82,80

Answer 2

hiii!!!

here's ur answer...

Pythagoras triplets are 2n, n²+1 and n²-1

let 18 be 2n

therefore n=18/2

=9

1. 18


2. n²+1

=9²+1

=81+1

=82

3. n²-1

=9²-1

=81-1

=80

hence the three Pythagoras triplets are 18,82 and 80.

hope this helps..!