Question

find the probability of getting at most three heads in tossing a coin three times.

Answer 1

1 (HHH)(HHT)(HTH)(THH)(TTT)(TTH)(THT)(HTT)

Answer 2

Answer:

Step-by-step explanation:

Let the event be tossing a coin 3 times

Head =H

Tail =T

Number of exhaustive events=n(s)

n(s)=9(HTH,HTT,HHT,HHH,

THT,THH,TTH,TTT )

Number of favorable events =n(e)

n(e)=8(HTH,HTT,HHT,HHH,

THT,THH,TTH)

Probability =n(s)/n(e)

=9/8