Question

Find the probability of getting head when a coin is tossed once. Also find the probability of getting a tail.​

Answer 1

Answer:

Step-by-step explanation:

To Find :-

Getting head when a coin is tossed once.

The probability of getting a tail.

Formula to be used :-

P = Number of favorable outcome/Total number of outcomes.

Solution :-

Total Number of outcomes = 2 (either head or tail)

Number of outcomes of head = 1

P (Head) = Number of favorable outcome/Total number of outcomes.

P (Head) = 1/2.

Number of outcomes of tail = 1

P (tail) = Number of favorable outcome/Total number of outcomes.

P (tail) = 1/2.

Hence, the probability of getting head is 1/2 and the probability of getting a tail is 1/2.

Answer 2

$To find = \begin{cases}</p><p></p><p>1 ) & \text{Getting head when a coin is tossed once} \\</p><p></p><p>2 ) & \text{The probability of getting a tail}</p><p></p><p>\end{cases}$

$\green{Formula\:should\:be\:used}$

p(E) = $\frac{No.\:of\:favourable\:outcomes}{Total\:no.\:of\:outcomes}$

$\huge{\orange{\underline{\red{\mathbb{SOLUTION:-}}}}}$

The total no. of outcomes either head or tail = 2

No. of outcomes of head = 1

P( Head) = $\frac{No.\:of\:favourable\:outcomes}{Total\:no.\:of\:outcomes}$

So, P(Head) = $\huge\frac{1}{2}$

Number of outcomes of tail = 1

Same process in tails also.

Then we get P(Tail) = $\huge\frac{1}{2}$

:$\implies$ Probability of getting heads = $\huge\pink{\frac{1}{2}}$

:$\implies$ Probability of getting tails = $\huge\red{\frac{1}{2}}$