Math, asked by Anonymous, 1 year ago

Find the probability of having 53 Sundays in
1. leap year 2. a non leap year

Answers

Answered by Amrutha321
1
in leap year 2/7

in non leap year 1/7

Anonymous: hey! can you explain me that how did you got the answer
Answered by Anonymous
1

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the probability of getting 53 sundays in leap year= 1 /7

6/7 or 0.86 is probability for 52 Sundays in a non-leap year. The odd day may be either Sunday, Monday, Tuesday, Wednesday, Thursday, Friday or Saturday. Therefore, the total number of possible outcomes or elements of a sample space is 7. 0.86 is probability for 52 Sundays in a non-leap year.

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