Math, asked by priyaaidasani24, 4 months ago

find the probability of not getting 53 tuesdays and 53 wednesdays in a leap year

Answers

Answered by ashoksavitayadav1001

0

Answer:

In a not leap years,there are 365 days in which

52 weeks and one days extra

It may be Mon , tue , wed , thu ,fri , sat , sun

therefore required probability

P ( 53 tuesday ) + P ( 53 wednesday )

P ( 53 tuesday 53 wednesday )

= 1upon 7 + 1upon 7 — 0 = 2upon 7

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