Find the probability that 4 digit number formed is an odd number if the digits are 0 1 2 3 4 5
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We have the digits 1,2,4,5,6,9
Four digit odd number ie the ending digit is from the set {1,5,9}
So for each of the 3 digits above the remaining 3 digits can be chosen and arranged within themselves, from remaining 5 digits in 5P3=60 ways.
So total arrangements ie distinct numbers=60*3=180
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