Question

find the probability that a common year not a leap year contains only 52 Sunday

Answer 1

Solution:

A non-leap year has 365 days

A year has 52 weeks. Hence there will be 52 Sundays for sure.

52 weeks = 52 x 7 = 364 days .

365– 364 = 1day extra.

In a non-leap year there will be 52 Sundays and 1day will be left.

This 1 day can be Sunday, Monday,Tuesday, Wednesday, Thursday,friday,Saturday, Sunday.

Of these total 7 outcomes, the favourable outcomes are 1.

Hence the probability of getting 53 sundays = 1 / 7. 2) ∴ probability of getting 52 sundays = 1 - 1/ 7 = 6 / 7.

Answer 2

ANSWER....

in a non leap year tgere will be 52 Sundays and one day will be left. this one day can be Sunday, Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday.

of these,
total outcomes = 7
favourable outcome = 1

Probability of getting 52 sundays in non leap year = favourable outcome / total outcome

$= \frac{1}{7}$
$hope \: it \: helps$

$thanks$