Find the probability that a four-digit number comprising the digits 2, 5, 6 and 7 would be divisible by 4.
Ans.1/3(EXPLAIN HOW )
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Total 4 digit numbers comprising 2,5,6 and 7 = 4! = 24
For any number to be divisible by 4, its last two digits have to be divisible by 4.
Out of the 24 numbers, such numbers are: 2756, 7256, 5672, 6572, 6752, 7652, 2576 and 5276.
Required probability= 8/24 = 1/3
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