Question

Find the probability that a leap year has 53 wednesdays

Answer 1

$Heya \: @Meenak !!! \\ This \: is \: your \: answer. \\ To \: find :- \\ Probability \: of \: 53 \: Wednesdays \: in \: a \: \\ Leap \: Year. \\ \\ Now, \\ Solution :- \\ Days \: in \: a \: Leap \: Year = 366. \\ Weaks \: in \: the \: leap \: year = 366/7 \\ => Quotient= 52.... Remainder = 2. \\ Hence, \: there \: are \: 52 \: weeks \: and \\ two \: days \: in \: the \: leap \: year. \\ \\ As \: there \: are \: 52 \: weeks, \\ then \: there \: will \: be \: 52 \: Wednesday \\ for \: sure. \\ \\ Now, \: about \: the \: two \: days :- \\ \\ They \: can \: be \: of \: following \: combination.$
$Monday, \: Tuesday \\ Tuesday, \: Wednesday \\ Wednesday, \: Thursday \\ Thursday, \: Friday \\ Friday, \: Saturday \\ Saturday, \: Sunday \\ Sunday, \: Monday$
$So, \: there \: are \: 7 \: probabilities. \: \\ Out \: of \: which \: probablity \: of \\ getting \: Wednesday \: is \: 2. \\ \\ Hence, \: the \: probability \: of \: 53 \: \\ Wednesdays \\ \: in \: a \: Leap \: Year \: is \frac{2}{7} . \\ \\ \\ Hope \: It \: Helps.........$

Answer 2

hellooooo.....

Here is your answer...

A leap year has 366 days
52 weeks and 2 odd days.

The two odd days can be
{Sunday,Monday}

{Monday,Tuesday}

{Tuesday,Wednesday}

{Wednesday,Thursday}

{Thursday,Friday}

{Friday,Saturday

{Saturday,Sunday}.


there are 7 possibilities out of which 2 have a Sunday. So the probability of 53 Sundays is 2/7