Question

find the probability that a leap year selected at random will have 53 Sunday for 5 mark

Answer 1

hey dear here is your answer..

no of total out comes= 7 days
no of favourable outcomes = remainder of 366/7 = 2

so probability of a leap year having 53 Sunday=2/7

Answer 2

Leap year has 366 days..
it means it has (52×7)+2 days
52 complete weeks and 2 adjacent days...
Now let's find what can be on these 2 days
Monday - Tuesday
Tuesday - Wednesday
Wednesday - Thursday
Thursday - Friday
Friday - Saturday
Saturday -SUNDAY
SUNDAY - Monday
There are 7 such pairs of adjacent days
we have to find the probability that the leap year has 53 Sunday
so Sunday is coming 2 times in above pairs
so probablilty of getting 53 Sunday is
$\frac{2}{7}$