Question

Find the probability that a non leap year chosen at random has 52sundays, 53 sundays

Answer 1

Non Leap year = 366 days
= 52 weeks +1 day
Possibility of that 1 day is
Sunday, Monday, Tuesday, Wednesday, Thursday, Friday, Saturday
Total number of outcomes =7

i. Getting 52 Sundays
Number of favourable outcomes =6
Probability of getting 52 Sundays =6/7

ii.Getting 53 Sundays
Number of favourable outcomes =1
Probability of getting 53 Sundays = 1/7

Answer 2

Answer:

In a leap year there are 366 days. In 366 days, we have 522 weeks and 2 days, Thus we can say that leap year ah always 52 Sundays.

The remaining two days can be

(i) Sunday and Mondays

(ii) Mondays and Tuesdays

(iii) Tuesday and Wednesday

(iv) Wednesday and Thursday

(v) Thursday and Friday

(VI) Friday and Saturday

(vii) Saturady and Sunday.

From above it is clear that there are 7 elementary events associated with this random experiment.

Clearly the event A will happen if the last two days of the leap year are either Sunday and Monday or Saturday and Sunday.

∴ P (E) = n (E)/n (S) = 2/7