Question

find the probability that a non-leap year contains 53 Sundays

Answer 1

Total number of days in a non- leap year=365
365 days has 52 weeks and 1 day.
This 1 day can be Monday,Tuesday,Wednesday ,Thursday, Friday, Saturday or Sunday.
So,total no. of possible outcomes =7 and no. of favorable outcomes=1 [Sunday]
Therefore, P(E)= No. of favourable outcomes/Total no. of possible outcomes
P(E)=1/7