Find the probability that a year (not leap) selected at random will contain 53 Saturday.
Answers
Answer:
For a leap year to have either 53 Thursday or 53 Friday, it must have them in the two days. 52 weeks and 2 days. So we can have any of these combinations, a Wednesday and Thursday, a Thursday and Friday, a Friday and Saturday. Thus the probability is 3/7.
In a leap year there are 366 days .
In a leap year there are 366 days .We have,
In a leap year there are 366 days .We have, 366 days = 52 weeks and 2 days
In a leap year there are 366 days .We have, 366 days = 52 weeks and 2 daysThus, a leap year has always 52 Sundays.
In a leap year there are 366 days .We have, 366 days = 52 weeks and 2 daysThus, a leap year has always 52 Sundays.The remaining 2 days can be:
In a leap year there are 366 days .We have, 366 days = 52 weeks and 2 daysThus, a leap year has always 52 Sundays.The remaining 2 days can be:(i) Sunday and Monday
In a leap year there are 366 days .We have, 366 days = 52 weeks and 2 daysThus, a leap year has always 52 Sundays.The remaining 2 days can be:(i) Sunday and Monday(ii) Monday and Tuesday
In a leap year there are 366 days .We have, 366 days = 52 weeks and 2 daysThus, a leap year has always 52 Sundays.The remaining 2 days can be:(i) Sunday and Monday(ii) Monday and Tuesday (iii) Tuesday and Wednesday
In a leap year there are 366 days .We have, 366 days = 52 weeks and 2 daysThus, a leap year has always 52 Sundays.The remaining 2 days can be:(i) Sunday and Monday(ii) Monday and Tuesday (iii) Tuesday and Wednesday(iv) Wednesday and Thursday
In a leap year there are 366 days .We have, 366 days = 52 weeks and 2 daysThus, a leap year has always 52 Sundays.The remaining 2 days can be:(i) Sunday and Monday(ii) Monday and Tuesday (iii) Tuesday and Wednesday(iv) Wednesday and Thursday(v) Thursday and Friday
In a leap year there are 366 days .We have, 366 days = 52 weeks and 2 daysThus, a leap year has always 52 Sundays.The remaining 2 days can be:(i) Sunday and Monday(ii) Monday and Tuesday (iii) Tuesday and Wednesday(iv) Wednesday and Thursday(v) Thursday and Friday(vi) Friday and Saturday
In a leap year there are 366 days .We have, 366 days = 52 weeks and 2 daysThus, a leap year has always 52 Sundays.The remaining 2 days can be:(i) Sunday and Monday(ii) Monday and Tuesday (iii) Tuesday and Wednesday(iv) Wednesday and Thursday(v) Thursday and Friday(vi) Friday and Saturday(vii) Saturday and Sunday.
In a leap year there are 366 days .We have, 366 days = 52 weeks and 2 daysThus, a leap year has always 52 Sundays.The remaining 2 days can be:(i) Sunday and Monday(ii) Monday and Tuesday (iii) Tuesday and Wednesday(iv) Wednesday and Thursday(v) Thursday and Friday(vi) Friday and Saturday(vii) Saturday and Sunday.Clearly, there are seven elemetary events associated with this random experiment,
In a leap year there are 366 days .We have, 366 days = 52 weeks and 2 daysThus, a leap year has always 52 Sundays.The remaining 2 days can be:(i) Sunday and Monday(ii) Monday and Tuesday (iii) Tuesday and Wednesday(iv) Wednesday and Thursday(v) Thursday and Friday(vi) Friday and Saturday(vii) Saturday and Sunday.Clearly, there are seven elemetary events associated with this random experiment,Let A be the event that a leap year has 53 Sundays.
In a leap year there are 366 days .We have, 366 days = 52 weeks and 2 daysThus, a leap year has always 52 Sundays.The remaining 2 days can be:(i) Sunday and Monday(ii) Monday and Tuesday (iii) Tuesday and Wednesday(iv) Wednesday and Thursday(v) Thursday and Friday(vi) Friday and Saturday(vii) Saturday and Sunday.Clearly, there are seven elemetary events associated with this random experiment,Let A be the event that a leap year has 53 Sundays.Clearly, the event A will happen if the last two days of the leap year are either Sunday and Monday or Saturday and Sunday.
In a leap year there are 366 days .We have, 366 days = 52 weeks and 2 daysThus, a leap year has always 52 Sundays.The remaining 2 days can be:(i) Sunday and Monday(ii) Monday and Tuesday (iii) Tuesday and Wednesday(iv) Wednesday and Thursday(v) Thursday and Friday(vi) Friday and Saturday(vii) Saturday and Sunday.Clearly, there are seven elemetary events associated with this random experiment,Let A be the event that a leap year has 53 Sundays.Clearly, the event A will happen if the last two days of the leap year are either Sunday and Monday or Saturday and Sunday.∴ Favourable number of elementary events = 2
In a leap year there are 366 days .We have, 366 days = 52 weeks and 2 daysThus, a leap year has always 52 Sundays.The remaining 2 days can be:(i) Sunday and Monday(ii) Monday and Tuesday (iii) Tuesday and Wednesday(iv) Wednesday and Thursday(v) Thursday and Friday(vi) Friday and Saturday(vii) Saturday and Sunday.Clearly, there are seven elemetary events associated with this random experiment,Let A be the event that a leap year has 53 Sundays.Clearly, the event A will happen if the last two days of the leap year are either Sunday and Monday or Saturday and Sunday.∴ Favourable number of elementary events = 2Hence, required probability = 2/7