Question

Find the probability that almost 5 defective fuses will be found in a box of 200 fuses , if experience show

that 2% of such fuses are defective. Given exp(-4)=

0.0183​

Answer 1

Answer:

The probability that atmost 5 defective fuses will be found in a box of 200 fuses, if experience shows that 20% of such fuses are defective, is

x=0

∑

5

x!

e

−40

40

x

Step-by-step explanation:

The poisson distribution is

P(X=x)=

x!

e

−λ

λ

x

, x=0,1,2,3,..

Let, X denote the defective fuse

p=

100

20

n=200

mean=λ=np=200×

100

20

=40

=>P(atmost 5 defective fuses)=

x=0

5

∑

x!

e

−40

40

x