Question

Find the probability that an ordinary year has 53 Sundays

Answer 1

let the outcome in a year be 365 days
and the no of Sunday is 53.
let p(E) be the probability.
we know that ,
p(E)=no. of favourable outcome/total no. of outcome
=53/ 365
=.14520
hope it's the required answer....

Answer 2

let,

        in an random experiment of getting sundays

total no of days in a non leap year         =         365

no of days in a week                                =          7

no of sundays                                           =         52*1/7  

p(getting sunday)                                       =        no of favourable            

                                                                          outcomes/total no of outcomes

                                                                    =    1/7