find the probablity of getting 53 friday in sleap year
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A leap year consists of 366 days.i.e 52 weeks and 2 days remaining.
These 2 days can be any of the following:
(Mon, Tues),(Tues,Wed),(Wed,Thurs),(Thurs,Fri),(Fri,Sat),(Sat,sun).
The number of cases = 7.
The number of cases in which we get a Friday = 2.
The probability of getting 53 Fridays in a leap year = 2/7.
Hope this helps!
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