Find the product :(2p+3q)*(2p-3q)*(4p²-9q²)
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Answer:
=(2p+3q)*(2p-3q)*(4p^2-9q^2)
=(4p^2-9q^2)*(4p^2-3q^2)
as a^2-b^2=(a+b)(a-b)
=16p^2-18q^2
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