Math, asked by zfdgmzfhmdzngxh, 1 year ago

find the product and answer​

Attachments:

shadowsabers03: The answer is x^3 + y^2 - z^3 + 3xyz.

Answers

Answered by Anonymous
7

Hey Buddy ... !! here is ur answer

Hope it will be helpful for you ✌️✌️

Attachments:

stylish23: Nice hand writing
Anonymous: Thanks ☺️
shadowsabers03: Why you have taken z instead of -z?
Answered by shadowsabers03
4

To solve it, we have to be familiar with the identity given below.

\large (a+b+c)(a^2+b^2+c^2-ab-bc-ca)=a^3+b^3+c^3-3abc

Taking,

a=x\\ \\ b=y\\ \\ c=-z

we get that,

\begin{aligned}&(x+y-z)(x^2+y^2+z^2-xy+yz+xz)\\ \\ \Longrightarrow\ \ &(x+y+(-z))(x^2+y^2+(-z)^2-xy-(-yz)-(-zx))\\ \\ \Longrightarrow\ \ &(a+b+c)(a^2+b^2+c^2-ab-bc-ca)\\ \\ \Longrightarrow\ \ &a^3+b^3+c^3-3abc\\ \\ \Longrightarrow\ \ &x^3+y^3+(-z)^3-3xy(-z)\\ \\ \Longrightarrow\ \ &x^3+y^3-z^3+3xyz\end{aligned}

Hence expanded it and found out the product!

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