find the product and their values for a = -1 , b= 2, c= 1 (4a-2b+3c)(2a-3b) ????????
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-24 is the obtained value
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Hey your answer is Here!!!!!!!!!!!!!!!
(4a-2b+3c) (2a-3b)
(4×(-1)-2×2+3×2)(2×(-1)-3×2)
(-4-4+6)(-2-6)
(-4+2)(-8)
-2×(-8)
16
(4a-2b+3c) (2a-3b)
(4×(-1)-2×2+3×2)(2×(-1)-3×2)
(-4-4+6)(-2-6)
(-4+2)(-8)
-2×(-8)
16
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