Question

find the product and verify the results by taking a=2 b=1 c=-3 (4b+5c) (b-c)​

Answer 1

-3[4*1+5*-3)(1+3)

-3(4-15)4

-48+180

=142

Answer 2

Step-by-step explanation:

give a=2,b=1andc=-3

put the value of all variables (alfabet) in the given equation which is (4b+5c)(b-c)

so,

you will get

(4(1)+5(-3))(1-(-3))

=>(4-15)(1+3)

=>-11*4

=>-44

product 4b(b-c)+5c(b-c)

4b^2-4bc+5bc-5c^2=>4b^2+bc-5c^2

put the values of a,b,c

4*(1)^2+(1)(-3)-5*(-3)^2

4-3-45=-44

hence prove

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