Find the product:
(i) (a+3)(a+5),
(ii) (3t+1)(3t+4);
(iii) (a−8)(a+2);
(iv) (a−6)(a−2).
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Answered by
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a²+ 5a+ 3a+ 15= a²+ 8a + 15 =
a² + 3a +5a +15 =
a(a+3) + 5 (a +3)
(a+5) (a+3)
a+5=0 or a+3=0
a=-5 or a=-3
a² + 3a +5a +15 =
a(a+3) + 5 (a +3)
(a+5) (a+3)
a+5=0 or a+3=0
a=-5 or a=-3
Answered by
1
products, Factors & Zeroes
all are founded out in the pic by Your Bhai
all are founded out in the pic by Your Bhai
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