Question

Find the product in two different ways by rearranging numbers

$\frac{24}{25} \times \frac{ - 75}{72} \times \frac{ - 18}{45}$
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please answer this question

Answer 1

$\frac{24}{25} \times \frac{ - 75}{72} \times \frac{ - 18}{45} \\ = (\frac{24}{25} \times \frac{ - 75}{72}) \times \frac{ - 18}{45} \\ = \frac{ - 3}{3} \times \frac{ - 18}{45} \\ = \frac{18}{45} \\ \\ and \\ \: \: \: \: \: \: \: \: \frac{24}{25} \times ( \frac{ - 75}{72} \times \frac{ - 18}{45}) \\ = \frac{24}{25} \times \frac{15}{4 \times 9} \\ = \frac{2}{5}$