Question

find the product of [1\2x^3] [-10x] [1\5x^2] and verify that x is 1

Answer 1

(1/2x)^3=1/8x^3

1/8x^3*(-10x) =-10/8x^2

(-10/8x^2)*(1/5x^2) =(-10/80x^2) it is product

put value of x is equal to 1

((1/2(1)^3) (-10(1))(1/5(1)^2)=(-1)

Answer 2

Answer:

Step-by-step explanation:

(1/2x)^3=1/8x^3

1/8x^3*(-10x) =-10/8x^2

(-10/8x^2)*(1/5x^2) =(-10/80x^2) it is product

put value of x is equal to 1

((1/2(1)^3) (-10(1))(1/5(1)^2)=(-1)