find the product of [1\2x^3] [-10x] [1\5x^2] and verify that x is 1
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(1/2x)^3=1/8x^3
1/8x^3*(-10x) =-10/8x^2
(-10/8x^2)*(1/5x^2) =(-10/80x^2) it is product
put value of x is equal to 1
((1/2(1)^3) (-10(1))(1/5(1)^2)=(-1)
Answered by
5
Answer:
Step-by-step explanation:
(1/2x)^3=1/8x^3
1/8x^3*(-10x) =-10/8x^2
(-10/8x^2)*(1/5x^2) =(-10/80x^2) it is product
put value of x is equal to 1
((1/2(1)^3) (-10(1))(1/5(1)^2)=(-1)
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