Question

find the product of 2/7x2(7y+14x) and verify the result when x=2 and y=3

Answer 1

Answer:

2x²y + 4x³

Step-by-step explanation:

2/7 x² ( 7y + 14x )

= (2/7 x² * 7y) + (2/7x² * 14x)

=   2x²y + 4x³

verification when x= 2 and y = 3.

L.H.S :

(2/7 x² * 7y) + (2/7x² * 14x)

(2/7 * 2 *2 *7* 3 ) + (2/7 * 2 * 2 * 14 * 2)

= (8/7*21)+(8/7*28)

=(8*3)+(8*4)

= 24 + 32 = 56

R.H.S:

2x²y + 4x^3

= (2* 2 *2 * 3) + (4 * 2 * 2 *2)

= 24 + 32

= 56

Therefore L.H.S = R.H.S

Answer 2

Answer:

2x²y + 4x³

Step-by-step explanation:

2/7 x² ( 7y + 14x )

= (2/7 x² * 7y) + (2/7x² * 14x)

=   2x²y + 4x³

verification when x= 2 and y = 3.

L.H.S :

(2/7 x² * 7y) + (2/7x² * 14x)

(2/7 * 2 *2 *7* 3 ) + (2/7 * 2 * 2 * 14 * 2)

= (8/7*21)+(8/7*28)

=(8*3)+(8*4)

= 24 + 32 = 56

R.H.S:

2x²y + 4x^3

= (2* 2 *2 * 3) + (4 * 2 * 2 *2)

= 24 + 32

= 56

Therefore L.H.S = R.H.S

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