Math, asked by blankspace39, 3 months ago

find the product of 2a²+4b²-3ab and 3ab-5a²+4b²
ans- 21a³b - 21a²b² - 10a^4 + 16b^4??

Answers

Answered by CopyThat
5

Given

  • 2a²+4b²-3ab
  • 3ab-5a²+4b²

To find

  • Product

Solution

→ (2a²+4b²-3ab) (3ab-5a²+4b²)

→ (2a²+4b²-3ab)(3ab) + (2a²+4b²-3ab)(-5a²)+(2a²+4b²-3ab)(4b²)

→ (6a³b+12ab³-9a²b²-10a⁴-20a²b²+15a³b+8a²b+16b⁴-12ab³)

21a³-21a²b²-10a⁴+16b⁴

∴ Product of 2a²+4b²-3ab and 3ab-5a²+4b² :-

  • 21a³-21a²b²-10a⁴+16b⁴

Learn more

  • https://brainly.in/question/35293095
  • 2x³-4x²-5 by 3x²+4x-2
Answered by Anonymous
24

Answer:

(2a²+4b²-3ab) (3ab-5a²+4b²)

→ (2a²+4b²-3ab)(3ab) + (2a²+4b²-3ab)(-5a²)+(2a²+4b²-3ab)(4b²)

→ (6a³b+12ab³-9a²b²-10a⁴-20a²b²+15a³b+8a²b+16b⁴-12ab³)

→ 21a³-21a²b²-10a⁴+16b⁴

∴ Product of 2a²+4b²-3ab and 3ab-5a²+4b² :-

21a³-21a²b²-10a⁴+16b⁴

Step-by-step explanation:

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