Question

The length of a rectangle is twice its width. If its perimeter is 54 cm, find its length. Also, then find its area.

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Answer 1

$\begin{gathered}{\underline{\underline{\maltese{\Huge{\textsf{\textbf{\red{Solution: }}}}}}}}\end{gathered}$

$\sf{\underline{Given:-}}$

• $\sf{Perimeter= 54cm}$

$\sf{\underline{To\: Find:-}}$

$\sf{Length \: of \: rectangle=?}$

$\sf{Area \: of \: rectangle=?}$

$\sf{Let, width \: of \: rectangle \: be \: x}$

$\sf{Then, length = 2×x = 2x}$

$\huge\sf{\underline{According \: to \: que.,}}$

$\sf{Perimeter\: of\: Rectangle= 2×(l+w)}$

$\dashrightarrow\sf{54 = 2×(2x+x})$

$\dashrightarrow\sf{54 = 2×3x}$

$\dashrightarrow\sf{54= 6x}$

$\dashrightarrow\sf{x = \frac{54}{6}}$

$\dashrightarrow\sf{x = 9cm}$

$\sf{So, width = x =\fbox\green{9cm}}$

$\sf{And, Length = 2x = 2 \times 9 =\fbox\green{ 18cm}}$

Now, we have to find Area of rectangle.

Formula:-

$\sf{Area \: of \: rectangle = l×w}$

$\dashrightarrow\sf{9×18cm}$

$\dashrightarrow\sf{Area = \fbox\purple{162cm}}$

Answer 2

Step-by-step explanation:

Given,

perimeter = 54 cm

To find,

length

width

and area

Let the width of the rectangle = x

and let the length of the rectangle = 2x

A. T. Q

perimeter of rectangle = 2(l+b)

54cm = 2( 2x + x)

54cm = 4x + 2x

54cm = 6x

54/6 cm = x

9 cm = x

width = x

= 9cm

length = 2x

= 2*9cm

= 18 cm

Area of rectangle = ( l X b)

= ( 18 X 9 ) cm²

= 162 cm²

HOPE THIS MAY HELP YOU!