Question

.Find the product of-2x² and (x-5)

.Solve 5(z-3)-4(z-2)=0

.Simplify ( 4x X 3y)² using identity

.(2⁻¹ X 5⁻¹) ÷ 4⁻²

.(1/2)⁻² + (1/2)⁻² + (1/4)⁻²

.Evaluate [(4/3)⁻¹ - (1/4)⁻¹]⁻¹

.EVALUATE (5² +3³)⁰÷6⁰

.Find the value of x for which
5²ˣ⁺¹÷25=125
[4/9]⁴ X [4/9]⁻⁷=[4/9]²ˣ⁻¹

.Add the following
5x²+3x-8, 4x+7 and 6-5+4x²
8x²-5xy+3y², 2xy-6y²+3x² and y²+2y-6x²

.subtract the following
5y⁴-3y³+2y²+y-1 from 4y²-2y³-6y²-y+5

.find the product
(5x+7) (3x+4)
(3y+8) (5y-1)
(5x²-6x+9) (2x-3)

( answer all question correctly and in English )

Answer 1

Kabhi bhi zindagi mein Hindi bolne se ghabrana nhi. Angrezi in Angrezo ki bhasha hai hamari bhasha Hindi hai aur agar koi vyakti ise hi bolne se katrata hai vo bhi ek Bhartiya hokar for to vo Insaan usi thali mein chhed kr rha hai jisme vo khata hai. Mera irada aapko thes pohunchane ka nhi tha . Main sirf apko ek cheez batana chahta tha. to kripya karke iska Dhyan rakhna bhavishya mein aur yeh saare questions dene ke liye dhanyavaad Mera bhi inse abhyas ho gya. But don't think I can't speak English I can even I can show it to you.