Question

Find the product of : 2y^3 x (-y)^2 x 3xy​

Answer 1

$2 {y}^{3} \times { (- y)}^{2} \times 3xy$

$= 2 {y}^{3} \times {y}^{2} \times 3xy$

$= 2 {y}^{5} \times 3xy$

$= 6x {y}^{6}$

Hence, this is the required answer.

Hope, it helps !

Answer 2

Answer:

Multiply: (2x2−3xy+y2) by (2y2−xy−x2)

Answer: 6x2y2+x3y−7xy3+2y4−2x4Multiplying term by term and then adding,

(2x2−3xy+y2)×(2y2−xy−x2)

=2x2(2y2−xy−x2)−3xy(2y2−xy−x2)+y2(2y2−xy−x2)

=4x2y2−2x3y−2x4−6xy3+3x2y2+3x3y+2y4−xy3−x2y2

=6x2y2−x3y−7xy3+2y4−2x4