Question

find the product of 3x³y³ and(2x-3y) also verify the answer​

Answer 1

Answer:

3x

3

y

2

×(2x−3y)

=3x

3

y

2

⋅2x−3x

3

y

2

⋅3y

=6x

4

y

2

−9x

3

y

3

Now, for x=−1,y=2, we have

L.H.S.-

3x

3

y

2

×(2x−3y)

=3(−1)

3

(2)

2

(2⋅(−1)−3⋅(2))

=3⋅(−1)⋅4×(−2−6)

=(−12)×(−8)

=96

R.H.S.-

6x

4

y

2

−9x

3

y

3

=6(−1)

4

(2)

2

−9(−1)

3

(2)

3

=6⋅1⋅4−9⋅(−1)⋅8

=24+72

=96

∵ L.H.S. = R.H.S.

Hence verified.

Answer 2

Answer:

6x^4y^3 -- 9x^3y^4

Step-by-step explanation:

(3x^3 y^3) × (2x-3y)

= 6x^4y^3 --9x^3y^4