Question

in the given figure PR perpendicular RT and angle P :angle Q : angle R = to 3 : 2 :1. find the value of angle TRS​

Answer 1

$\large \underline\red{\sf \pmb{ Answer :-}}$

P:Q:R = 3:2:1

Let Angles = 3x, 2x, x

P + Q + R = 180° (Angle Sum Property of a triangle)

=> 3x + 2x + x = 180

=> 6x = 180

=> x = 30°

P = 90°

Q = 60°

R = 30°

/_TRS = 180° - (/_TRP + /_PRQ) [Linear Pair]

=> /_TRS = 180 - 30 - 90

=> /_TRS = 60°

Answer 2

P:Q:R = 3:2:1

Let Angles = 3x, 2x, x

P + Q + R = 180° (Angle Sum Property of a triangle)

=> 3x + 2x + x = 180

=> 6x = 180

=> x = 30°

P = 90°

Q = 60°

R = 30°

/_TRS = 180° - (/_TRP + /_PRQ) [Linear Pair]

=> /_TRS = 180 - 30 - 90

=> /_TRS = 60°

Please mark me as brainliest. I have only 5 brainliest answers to become Ace.