Question

find the product of (-3xyz) (4/9x(2)z)(-27/2xy^2z)and verify the result for x=2,y=3 and z=-1.​

Answer 1

Answer:

=−3xyz(49x2z)(−272xy2z)

=(−43x3yz)(−272xy2z)=

18x4y3z2

Now,

x=2,

y=3

z=−1

Verify:

=18(2) 4(3) 3 (−1)2

=18×16×27×1

=7776

∴Verified