Find the product of (4a2+1)(4a2+3) using suitable identity.
please answer with step by step explanation
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Answered by
2
Answer:
Is it 4a²?
However, the identity would be
a²+ (b+c)a + bc
.
where a is the number common in both,
b is 1 and c is 3 in the above question.
.
If it's (4a²+1)(4a²+3) then,
.
(4a²)² + (1+3)4a² + 3×1
.
16a⁴ + 16a² + 3
.
Here's your answer: 16a⁴ + 16a² + 3
Answered by
0
Answer:
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